3v+5(v+5)=-32+7v

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Solution for 3v+5(v+5)=-32+7v equation: 



3v+5(v+5)=-32+7v

We move all terms to the left:

3v+5(v+5)-(-32+7v)=0

We add all the numbers together, and all the variables

3v+5(v+5)-(7v-32)=0

We multiply parentheses

3v+5v-(7v-32)+25=0

We get rid of parentheses

3v+5v-7v+32+25=0

We add all the numbers together, and all the variables

v+57=0

We move all terms containing v to the left, all other terms to the right

v=-57

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