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2/3g+1/2g=44
We move all terms to the left:
2/3g+1/2g-(44)=0
Domain of the equation: 3g!=0
g!=0/3
g!=0
g∈R
Domain of the equation: 2g!=0We calculate fractions
g!=0/2
g!=0
g∈R
4g/6g^2+3g/6g^2-44=0
We multiply all the terms by the denominator
4g+3g-44*6g^2=0
We add all the numbers together, and all the variables
7g-44*6g^2=0
Wy multiply elements
-264g^2+7g=0
a = -264; b = 7; c = 0;
Δ = b2-4ac
Δ = 72-4·(-264)·0
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{49}=7$$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-7}{2*-264}=\frac{-14}{-528} =7/264 $$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+7}{2*-264}=\frac{0}{-528} =0 $
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