3v+4-2(-6v-1)=5(v-2)

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Solution for 3v+4-2(-6v-1)=5(v-2) equation: 



3v+4-2(-6v-1)=5(v-2)

We move all terms to the left:

3v+4-2(-6v-1)-(5(v-2))=0

We multiply parentheses

3v+12v-(5(v-2))+2+4=0



We calculate terms in parentheses: -(5(v-2)), so:

5(v-2)

We multiply parentheses

5v-10

Back to the equation:

-(5v-10)



We add all the numbers together, and all the variables

15v-(5v-10)+6=0

We get rid of parentheses

15v-5v+10+6=0

We add all the numbers together, and all the variables

10v+16=0

We move all terms containing v to the left, all other terms to the right

10v=-16

v=-16/10

v=-1+3/5

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