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12x^2+36x=120
We move all terms to the left:
12x^2+36x-(120)=0
a = 12; b = 36; c = -120;
Δ = b2-4ac
Δ = 362-4·12·(-120)
Δ = 7056
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{7056}=84$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(36)-84}{2*12}=\frac{-120}{24} =-5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(36)+84}{2*12}=\frac{48}{24} =2 $
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