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3u(1/u)=0
Domain of the equation: u)!=0We add all the numbers together, and all the variables
u!=0/1
u!=0
u∈R
3u(+1/u)=0
We multiply parentheses
3u^2=0
a = 3; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·3·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$u=\frac{-b}{2a}=\frac{0}{6}=0$
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