3t-18=(-12)-3t

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Solution for 3t-18=(-12)-3t equation: 



3t-18=(-12)-3t

We move all terms to the left:

3t-18-((-12)-3t)=0



We calculate terms in parentheses: -((-12)-3t), so:

(-12)-3t

determiningTheFunctionDomain
-3t+(-12)

We add all the numbers together, and all the variables

-3t-12

Back to the equation:

-(-3t-12)



We get rid of parentheses

3t+3t+12-18=0

We add all the numbers together, and all the variables

6t-6=0

We move all terms containing t to the left, all other terms to the right

6t=6

t=6/6

t=1

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