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3x*2x=0.6
We move all terms to the left:
3x*2x-(0.6)=0
We add all the numbers together, and all the variables
3x*2x-0.6=0
Wy multiply elements
6x^2-0.6=0
a = 6; b = 0; c = -0.6;
Δ = b2-4ac
Δ = 02-4·6·(-0.6)
Δ = 14.4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{14.4}}{2*6}=\frac{0-\sqrt{14.4}}{12} =-\frac{\sqrt{}}{12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{14.4}}{2*6}=\frac{0+\sqrt{14.4}}{12} =\frac{\sqrt{}}{12} $
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