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3t+2=4/5(3+t)
We move all terms to the left:
3t+2-(4/5(3+t))=0
Domain of the equation: 5(3+t))!=0We add all the numbers together, and all the variables
t∈R
3t-(4/5(t+3))+2=0
We multiply all the terms by the denominator
3t*5(t+3))-(4+2*5(t+3))=0
Wy multiply elements
15t^2(t+10t(t=0
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