3t+2(7-3t)=8-(4-12t)

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Solution for 3t+2(7-3t)=8-(4-12t) equation: 



3t+2(7-3t)=8-(4-12t)

We move all terms to the left:

3t+2(7-3t)-(8-(4-12t))=0

We add all the numbers together, and all the variables

3t+2(-3t+7)-(8-(-12t+4))=0

We multiply parentheses

3t-6t-(8-(-12t+4))+14=0



We calculate terms in parentheses: -(8-(-12t+4)), so:

8-(-12t+4)

determiningTheFunctionDomain
-(-12t+4)+8

We get rid of parentheses

12t-4+8

We add all the numbers together, and all the variables

12t+4

Back to the equation:

-(12t+4)



We add all the numbers together, and all the variables

-3t-(12t+4)+14=0

We get rid of parentheses

-3t-12t-4+14=0

We add all the numbers together, and all the variables

-15t+10=0

We move all terms containing t to the left, all other terms to the right

-15t=-10

t=-10/-15

t=2/3

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