z-10(z+1)=8(2+3z)+1

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Solution for z-10(z+1)=8(2+3z)+1 equation: 



z-10(z+1)=8(2+3z)+1

We move all terms to the left:

z-10(z+1)-(8(2+3z)+1)=0

We add all the numbers together, and all the variables

z-10(z+1)-(8(3z+2)+1)=0

We multiply parentheses

z-10z-(8(3z+2)+1)-10=0



We calculate terms in parentheses: -(8(3z+2)+1), so:

8(3z+2)+1

We multiply parentheses

24z+16+1

We add all the numbers together, and all the variables

24z+17

Back to the equation:

-(24z+17)



We add all the numbers together, and all the variables

-9z-(24z+17)-10=0

We get rid of parentheses

-9z-24z-17-10=0

We add all the numbers together, and all the variables

-33z-27=0

We move all terms containing z to the left, all other terms to the right

-33z=27

z=27/-33

z=-9/11

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