3s-(2+s=)

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Solution for 3s-(2+s=) equation: 



3s-(2+s=)

We move all terms to the left:

3s-(2+s-())=0



We calculate terms in parentheses: -(2+s-()), so:

2+s-()

determiningTheFunctionDomain
s+2-()

We add all the numbers together, and all the variables

s

Back to the equation:

-(s)



We add all the numbers together, and all the variables

2s=0

s=0/2

s=0

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