3s(15s-19)=0

Solution for 3s(15s-19)=0 equation:

3s(15s-19)=0

We multiply parentheses

45s^2-57s=0

a = 45; b = -57; c = 0;
Δ = b2-4ac
Δ = -572-4·45·0
Δ = 3249
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3249}=57$
$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-57)-57}{2*45}=\frac{0}{90}
=0
$
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-57)+57}{2*45}=\frac{114}{90}
=1+4/15
$