-7(-2y+4)-4y=2(y-3)-8

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Solution for -7(-2y+4)-4y=2(y-3)-8 equation: 



-7(-2y+4)-4y=2(y-3)-8

We move all terms to the left:

-7(-2y+4)-4y-(2(y-3)-8)=0

We add all the numbers together, and all the variables

-4y-7(-2y+4)-(2(y-3)-8)=0

We multiply parentheses

-4y+14y-(2(y-3)-8)-28=0



We calculate terms in parentheses: -(2(y-3)-8), so:

2(y-3)-8

We multiply parentheses

2y-6-8

We add all the numbers together, and all the variables

2y-14

Back to the equation:

-(2y-14)



We add all the numbers together, and all the variables

10y-(2y-14)-28=0

We get rid of parentheses

10y-2y+14-28=0

We add all the numbers together, and all the variables

8y-14=0

We move all terms containing y to the left, all other terms to the right

8y=14

y=14/8

y=1+3/4

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