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3r+2=3(r-1)
We move all terms to the left:
3r+2-(3(r-1))=0
We calculate terms in parentheses: -(3(r-1)), so:We get rid of parentheses
3(r-1)
We multiply parentheses
3r-3
Back to the equation:
-(3r-3)
3r-3r+3+2=0
We add all the numbers together, and all the variables
5!=0
There is no solution for this equation
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