3r+2(3-2r)=18+5r

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Solution for 3r+2(3-2r)=18+5r equation: 



3r+2(3-2r)=18+5r

We move all terms to the left:

3r+2(3-2r)-(18+5r)=0

We add all the numbers together, and all the variables

3r+2(-2r+3)-(5r+18)=0

We multiply parentheses

3r-4r-(5r+18)+6=0

We get rid of parentheses

3r-4r-5r-18+6=0

We add all the numbers together, and all the variables

-6r-12=0

We move all terms containing r to the left, all other terms to the right

-6r=12

r=12/-6

r=-2

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