2(2y-4)=3(2y-1)+9

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Solution for 2(2y-4)=3(2y-1)+9 equation: 



2(2y-4)=3(2y-1)+9

We move all terms to the left:

2(2y-4)-(3(2y-1)+9)=0

We multiply parentheses

4y-(3(2y-1)+9)-8=0



We calculate terms in parentheses: -(3(2y-1)+9), so:

3(2y-1)+9

We multiply parentheses

6y-3+9

We add all the numbers together, and all the variables

6y+6

Back to the equation:

-(6y+6)



We get rid of parentheses

4y-6y-6-8=0

We add all the numbers together, and all the variables

-2y-14=0

We move all terms containing y to the left, all other terms to the right

-2y=14

y=14/-2

y=-7

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