3p2+16p-59=p

Solution for 3p2+16p-59=p equation:

3p^2+16p-59=p

We move all terms to the left:

3p^2+16p-59-(p)=0

We add all the numbers together, and all the variables

3p^2+15p-59=0

a = 3; b = 15; c = -59;
Δ = b2-4ac
Δ = 152-4·3·(-59)
Δ = 933
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-\sqrt{933}}{2*3}=\frac{-15-\sqrt{933}}{6}
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+\sqrt{933}}{2*3}=\frac{-15+\sqrt{933}}{6}
$