3n2+3n-7056=0

Solution for 3n2+3n-7056=0 equation:

3n^2+3n-7056=0

a = 3; b = 3; c = -7056;
Δ = b2-4ac
Δ = 32-4·3·(-7056)
Δ = 84681
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{84681}=291$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-291}{2*3}=\frac{-294}{6}
=-49
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+291}{2*3}=\frac{288}{6}
=48
$