(4x+1)(1-x)=0

Solution for (4x+1)(1-x)=0 equation:

(4x+1)(1-x)=0

We add all the numbers together, and all the variables

(4x+1)(-1x+1)=0

We multiply parentheses ..

(-4x^2+4x-1x+1)=0

We get rid of parentheses

-4x^2+4x-1x+1=0

We add all the numbers together, and all the variables

-4x^2+3x+1=0

a = -4; b = 3; c = +1;
Δ = b2-4ac
Δ = 32-4·(-4)·1
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25}=5$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-5}{2*-4}=\frac{-8}{-8}
=1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+5}{2*-4}=\frac{2}{-8}
=-1/4
$