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3n(5n+10)=0
We multiply parentheses
15n^2+30n=0
a = 15; b = 30; c = 0;
Δ = b2-4ac
Δ = 302-4·15·0
Δ = 900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{900}=30$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(30)-30}{2*15}=\frac{-60}{30} =-2 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(30)+30}{2*15}=\frac{0}{30} =0 $
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