3n(2n+9)=n(6n+2)-5

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Solution for 3n(2n+9)=n(6n+2)-5 equation: 



3n(2n+9)=n(6n+2)-5

We move all terms to the left:

3n(2n+9)-(n(6n+2)-5)=0

We multiply parentheses

6n^2+27n-(n(6n+2)-5)=0



We calculate terms in parentheses: -(n(6n+2)-5), so:

n(6n+2)-5

We multiply parentheses

6n^2+2n-5

Back to the equation:

-(6n^2+2n-5)



We get rid of parentheses

6n^2-6n^2+27n-2n+5=0

We add all the numbers together, and all the variables

25n+5=0

We move all terms containing n to the left, all other terms to the right

25n=-5

n=-5/25

n=-1/5

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