19-4a=5(3a+1)-5a

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Solution for 19-4a=5(3a+1)-5a equation: 



19-4a=5(3a+1)-5a

We move all terms to the left:

19-4a-(5(3a+1)-5a)=0



We calculate terms in parentheses: -(5(3a+1)-5a), so:

5(3a+1)-5a

We add all the numbers together, and all the variables

-5a+5(3a+1)

We multiply parentheses

-5a+15a+5

We add all the numbers together, and all the variables

10a+5

Back to the equation:

-(10a+5)



We get rid of parentheses

-4a-10a-5+19=0

We add all the numbers together, and all the variables

-14a+14=0

We move all terms containing a to the left, all other terms to the right

-14a=-14

a=-14/-14

a=1

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