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3m=12-5/2m
We move all terms to the left:
3m-(12-5/2m)=0
Domain of the equation: 2m)!=0We add all the numbers together, and all the variables
m!=0/1
m!=0
m∈R
3m-(-5/2m+12)=0
We get rid of parentheses
3m+5/2m-12=0
We multiply all the terms by the denominator
3m*2m-12*2m+5=0
Wy multiply elements
6m^2-24m+5=0
a = 6; b = -24; c = +5;
Δ = b2-4ac
Δ = -242-4·6·5
Δ = 456
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{456}=\sqrt{4*114}=\sqrt{4}*\sqrt{114}=2\sqrt{114}$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-2\sqrt{114}}{2*6}=\frac{24-2\sqrt{114}}{12} $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+2\sqrt{114}}{2*6}=\frac{24+2\sqrt{114}}{12} $
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