5x2-(85+10)x+(205+40)=0

Solution for 5x2-(85+10)x+(205+40)=0 equation:

5x^2-(85+10)x+(205+40)=0

We add all the numbers together, and all the variables

5x^2-95x+245=0

a = 5; b = -95; c = +245;
Δ = b2-4ac
Δ = -952-4·5·245
Δ = 4125
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{4125}=\sqrt{25*165}=\sqrt{25}*\sqrt{165}=5\sqrt{165}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-95)-5\sqrt{165}}{2*5}=\frac{95-5\sqrt{165}}{10}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-95)+5\sqrt{165}}{2*5}=\frac{95+5\sqrt{165}}{10}
$