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3m^2=-9-12m
We move all terms to the left:
3m^2-(-9-12m)=0
We add all the numbers together, and all the variables
3m^2-(-12m-9)=0
We get rid of parentheses
3m^2+12m+9=0
a = 3; b = 12; c = +9;
Δ = b2-4ac
Δ = 122-4·3·9
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{36}=6$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-6}{2*3}=\frac{-18}{6} =-3 $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+6}{2*3}=\frac{-6}{6} =-1 $
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