-8+5-4(x-1)=-4x(7x-2)

Solution for -8+5-4(x-1)=-4x(7x-2) equation:

-8+5-4(x-1)=-4x(7x-2)

We move all terms to the left:

-8+5-4(x-1)-(-4x(7x-2))=0

We add all the numbers together, and all the variables

-4(x-1)-(-4x(7x-2))-3=0

We multiply parentheses

-4x-(-4x(7x-2))+4-3=0


We calculate terms in parentheses: -(-4x(7x-2)), so:

-4x(7x-2)

We multiply parentheses

-28x^2+8x

Back to the equation:

-(-28x^2+8x)


We add all the numbers together, and all the variables

-(-28x^2+8x)-4x+1=0

We get rid of parentheses

28x^2-8x-4x+1=0

We add all the numbers together, and all the variables

28x^2-12x+1=0

a = 28; b = -12; c = +1;
Δ = b2-4ac
Δ = -122-4·28·1
Δ = 32
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{32}=\sqrt{16*2}=\sqrt{16}*\sqrt{2}=4\sqrt{2}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-4\sqrt{2}}{2*28}=\frac{12-4\sqrt{2}}{56}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+4\sqrt{2}}{2*28}=\frac{12+4\sqrt{2}}{56}
$