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3m-7+2m(m=15)
We move all terms to the left:
3m-7+2m(m-(15))=0
We multiply parentheses
2m^2+3m-30m-7=0
We add all the numbers together, and all the variables
2m^2-27m-7=0
a = 2; b = -27; c = -7;
Δ = b2-4ac
Δ = -272-4·2·(-7)
Δ = 785
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-27)-\sqrt{785}}{2*2}=\frac{27-\sqrt{785}}{4} $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-27)+\sqrt{785}}{2*2}=\frac{27+\sqrt{785}}{4} $
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