-3(z-19)=12

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Solution for -3(z-19)=12 equation: 



-3(z-19)=12

We move all terms to the left:

-3(z-19)-(12)=0

We multiply parentheses

-3z+57-12=0

We add all the numbers together, and all the variables

-3z+45=0

We move all terms containing z to the left, all other terms to the right

-3z=-45

z=-45/-3

z=+15

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