3m(m-5)=m

Solution for 3m(m-5)=m equation:

3m(m-5)=m

We move all terms to the left:

3m(m-5)-(m)=0

We add all the numbers together, and all the variables

-1m+3m(m-5)=0

We multiply parentheses

3m^2-1m-15m=0

We add all the numbers together, and all the variables

3m^2-16m=0

a = 3; b = -16; c = 0;
Δ = b2-4ac
Δ = -162-4·3·0
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{256}=16$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-16}{2*3}=\frac{0}{6}
=0
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+16}{2*3}=\frac{32}{6}
=5+1/3
$