4(n-1)=2(n+4)

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Solution for 4(n-1)=2(n+4) equation: 



4(n-1)=2(n+4)

We move all terms to the left:

4(n-1)-(2(n+4))=0

We multiply parentheses

4n-(2(n+4))-4=0



We calculate terms in parentheses: -(2(n+4)), so:

2(n+4)

We multiply parentheses

2n+8

Back to the equation:

-(2n+8)



We get rid of parentheses

4n-2n-8-4=0

We add all the numbers together, and all the variables

2n-12=0

We move all terms containing n to the left, all other terms to the right

2n=12

n=12/2

n=6

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