3m(m-2)=5

Solution for 3m(m-2)=5 equation:

3m(m-2)=5

We move all terms to the left:

3m(m-2)-(5)=0

We multiply parentheses

3m^2-6m-5=0

a = 3; b = -6; c = -5;
Δ = b2-4ac
Δ = -62-4·3·(-5)
Δ = 96
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{96}=\sqrt{16*6}=\sqrt{16}*\sqrt{6}=4\sqrt{6}$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-4\sqrt{6}}{2*3}=\frac{6-4\sqrt{6}}{6}
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+4\sqrt{6}}{2*3}=\frac{6+4\sqrt{6}}{6}
$