2x(25/3)=7

Solution for 2x(25/3)=7 equation:

2x(25/3)=7

We move all terms to the left:

2x(25/3)-(7)=0

We add all the numbers together, and all the variables

2x(+25/3)-7=0

We multiply parentheses

50x^2-7=0

a = 50; b = 0; c = -7;
Δ = b2-4ac
Δ = 02-4·50·(-7)
Δ = 1400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1400}=\sqrt{100*14}=\sqrt{100}*\sqrt{14}=10\sqrt{14}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-10\sqrt{14}}{2*50}=\frac{0-10\sqrt{14}}{100}
=-\frac{10\sqrt{14}}{100}
=-\frac{\sqrt{14}}{10}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+10\sqrt{14}}{2*50}=\frac{0+10\sqrt{14}}{100}
=\frac{10\sqrt{14}}{100}
=\frac{\sqrt{14}}{10}
$