If it's not what You are looking for type in the equation solver your own equation and let us solve it.
3m(m-2)=11
We move all terms to the left:
3m(m-2)-(11)=0
We multiply parentheses
3m^2-6m-11=0
a = 3; b = -6; c = -11;
Δ = b2-4ac
Δ = -62-4·3·(-11)
Δ = 168
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{168}=\sqrt{4*42}=\sqrt{4}*\sqrt{42}=2\sqrt{42}$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-2\sqrt{42}}{2*3}=\frac{6-2\sqrt{42}}{6} $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+2\sqrt{42}}{2*3}=\frac{6+2\sqrt{42}}{6} $
| 7/6x=7.5 | | n+9=2 | | 2x=4x-72 | | (x+10)/x=12 | | 4x-x/2-3=12 | | (x+5)/x=6 | | x*0.02=115000 | | 3x-15=2x+10+180 | | x+5/x=6 | | 3x/4-1/2=0 | | 8x=2x+60+180 | | 2.5x+x=525 | | 10/12=x/7 | | 10/12=7/x | | 24b-48=6b-18 | | (6x+3)=(10x+1) | | 2/7(x−2)=4x | | 4b-12=16b-32 | | |3t-11|=22 | | -243=-9(10÷x) | | 20=6-0.3j | | 2w-4=-16 | | (100x-99)^3=(5x)^6 | | 5(100+-1.6y)+8y=500 | | 4x-3+47=280 | | 545.82=4x+17.82 | | 4(4+d)=3(2+2d) | | 12(4+j)=108 | | 13t=325 | | t(13)=5(65) | | F(x)=3x^2(5x^3+8) | | 216=6^(4x+11) |