4(4+d)=3(2+2d)

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Solution for 4(4+d)=3(2+2d) equation: 



4(4+d)=3(2+2d)

We move all terms to the left:

4(4+d)-(3(2+2d))=0

We add all the numbers together, and all the variables

4(d+4)-(3(2d+2))=0

We multiply parentheses

4d-(3(2d+2))+16=0



We calculate terms in parentheses: -(3(2d+2)), so:

3(2d+2)

We multiply parentheses

6d+6

Back to the equation:

-(6d+6)



We get rid of parentheses

4d-6d-6+16=0

We add all the numbers together, and all the variables

-2d+10=0

We move all terms containing d to the left, all other terms to the right

-2d=-10

d=-10/-2

d=+5

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