3k-4=k2+3

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Solution for 3k-4=k2+3 equation: 



3k-4=k2+3

We move all terms to the left:

3k-4-(k2+3)=0

We add all the numbers together, and all the variables

-(+k^2+3)+3k-4=0

We get rid of parentheses

-k^2+3k-3-4=0

We add all the numbers together, and all the variables

-1k^2+3k-7=0

a = -1; b = 3; c = -7;
Δ = b2-4ac
Δ = 32-4·(-1)·(-7)
Δ = -19
Delta is less than zero, so there is no solution for the equation

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