-6(2x+4)+1/2(8+3x)=-20

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Solution for -6(2x+4)+1/2(8+3x)=-20 equation: 



-6(2x+4)+1/2(8+3x)=-20

We move all terms to the left:

-6(2x+4)+1/2(8+3x)-(-20)=0



Domain of the equation: 2(8+3x)!=0

x∈R



We add all the numbers together, and all the variables

-6(2x+4)+1/2(3x+8)-(-20)=0

We add all the numbers together, and all the variables

-6(2x+4)+1/2(3x+8)+20=0

We multiply parentheses

-12x+1/2(3x+8)-24+20=0

We multiply all the terms by the denominator


-12x*2(3x+8)-24*2(3x+8)+20*2(3x+8)+1=0

Wy multiply elements

-24x^2(3-48x(3+40x(3+1=0

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