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3k-4=5+2(k-3)
We move all terms to the left:
3k-4-(5+2(k-3))=0
We calculate terms in parentheses: -(5+2(k-3)), so:We get rid of parentheses
5+2(k-3)
determiningTheFunctionDomain 2(k-3)+5
We multiply parentheses
2k-6+5
We add all the numbers together, and all the variables
2k-1
Back to the equation:
-(2k-1)
3k-2k+1-4=0
We add all the numbers together, and all the variables
k-3=0
We move all terms containing k to the left, all other terms to the right
k=3
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