3k+36=3(2k+5)

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Solution for 3k+36=3(2k+5) equation: 



3k+36=3(2k+5)

We move all terms to the left:

3k+36-(3(2k+5))=0



We calculate terms in parentheses: -(3(2k+5)), so:

3(2k+5)

We multiply parentheses

6k+15

Back to the equation:

-(6k+15)



We get rid of parentheses

3k-6k-15+36=0

We add all the numbers together, and all the variables

-3k+21=0

We move all terms containing k to the left, all other terms to the right

-3k=-21

k=-21/-3

k=+7

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