100(1-x)(1+x)=0

Solution for 100(1-x)(1+x)=0 equation:

100(1-x)(1+x)=0

We add all the numbers together, and all the variables

100(-1x+1)(x+1)=0

We multiply parentheses ..

100(-1x^2-1x+x+1)=0

We multiply parentheses

-100x^2-100x+100x+100=0

We add all the numbers together, and all the variables

-100x^2+100=0

a = -100; b = 0; c = +100;
Δ = b2-4ac
Δ = 02-4·(-100)·100
Δ = 40000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{40000}=200$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-200}{2*-100}=\frac{-200}{-200}
=1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+200}{2*-100}=\frac{200}{-200}
=-1
$