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3k+2/3=9
We move all terms to the left:
3k+2/3-(9)=0
determiningTheFunctionDomain 3k-9+2/3=0
We multiply all the terms by the denominator
3k*3+2-9*3=0
We add all the numbers together, and all the variables
3k*3-25=0
Wy multiply elements
9k-25=0
We move all terms containing k to the left, all other terms to the right
9k=25
k=25/9
k=2+7/9
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