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2/5z=3
We move all terms to the left:
2/5z-(3)=0
Domain of the equation: 5z!=0We multiply all the terms by the denominator
z!=0/5
z!=0
z∈R
-3*5z+2=0
Wy multiply elements
-15z+2=0
We move all terms containing z to the left, all other terms to the right
-15z=-2
z=-2/-15
z=2/15
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