3i(11+6i)=0

Solution for 3i(11+6i)=0 equation:

3i(11+6i)=0

We add all the numbers together, and all the variables

3i(6i+11)=0

We multiply parentheses

18i^2+33i=0

a = 18; b = 33; c = 0;
Δ = b2-4ac
Δ = 332-4·18·0
Δ = 1089
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$i_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$i_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1089}=33$
$i_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(33)-33}{2*18}=\frac{-66}{36}
=-1+5/6
$
$i_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(33)+33}{2*18}=\frac{0}{36}
=0
$