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2(x-7)-3(4x+4)=4-(5x-2)
We move all terms to the left:
2(x-7)-3(4x+4)-(4-(5x-2))=0
We multiply parentheses
2x-12x-(4-(5x-2))-14-12=0
We calculate terms in parentheses: -(4-(5x-2)), so:We add all the numbers together, and all the variables
4-(5x-2)
determiningTheFunctionDomain -(5x-2)+4
We get rid of parentheses
-5x+2+4
We add all the numbers together, and all the variables
-5x+6
Back to the equation:
-(-5x+6)
-10x-(-5x+6)-26=0
We get rid of parentheses
-10x+5x-6-26=0
We add all the numbers together, and all the variables
-5x-32=0
We move all terms containing x to the left, all other terms to the right
-5x=32
x=32/-5
x=-6+2/5
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