((6x-72)/8)=3x

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Solution for ((6x-72)/8)=3x equation: 



((6x-72)/8)=3x

We move all terms to the left:

((6x-72)/8)-(3x)=0

We add all the numbers together, and all the variables

-3x+((6x-72)/8)=0

We multiply all the terms by the denominator


-3x*8)+((6x-72)=0

Wy multiply elements

-24x^2=0

a = -24; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-24)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{-48}=0$

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