3c-68=c+24

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Solution for 3c-68=c+24 equation: 



3c-68=c+24

We move all terms to the left:

3c-68-(c+24)=0

We get rid of parentheses

3c-c-24-68=0

We add all the numbers together, and all the variables

2c-92=0

We move all terms containing c to the left, all other terms to the right

2c=92

c=92/2

c=46

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