2(4x+5)=31+1

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Solution for 2(4x+5)=31+1 equation: 



2(4x+5)=31+1

We move all terms to the left:

2(4x+5)-(31+1)=0

We add all the numbers together, and all the variables

2(4x+5)-32=0

We multiply parentheses

8x+10-32=0

We add all the numbers together, and all the variables

8x-22=0

We move all terms containing x to the left, all other terms to the right

8x=22

x=22/8

x=2+3/4

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