3c-(2c+6)=2(c-8)-c

Solution for 3c-(2c+6)=2(c-8)-c equation:

3c-(2c+6)=2(c-8)-c

We move all terms to the left:

3c-(2c+6)-(2(c-8)-c)=0

We get rid of parentheses

3c-2c-(2(c-8)-c)-6=0


We calculate terms in parentheses: -(2(c-8)-c), so:

2(c-8)-c

We add all the numbers together, and all the variables

-1c+2(c-8)

We multiply parentheses

-1c+2c-16

We add all the numbers together, and all the variables

c-16

Back to the equation:

-(c-16)


We add all the numbers together, and all the variables

c-(c-16)-6=0

We get rid of parentheses

c-c+16-6=0

We add all the numbers together, and all the variables

10!=0

There is no solution for this equation