7(x-5)+32=6x-6

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Solution for 7(x-5)+32=6x-6 equation: 



7(x-5)+32=6x-6

We move all terms to the left:

7(x-5)+32-(6x-6)=0

We multiply parentheses

7x-(6x-6)-35+32=0

We get rid of parentheses

7x-6x+6-35+32=0

We add all the numbers together, and all the variables

x+3=0

We move all terms containing x to the left, all other terms to the right

x=-3

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