3c+10=c+2=3c+16

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Solution for 3c+10=c+2=3c+16 equation: 



3c+10=c+2=3c+16

We move all terms to the left:

3c+10-(c+2)=0

We get rid of parentheses

3c-c-2+10=0

We add all the numbers together, and all the variables

2c+8=0

We move all terms containing c to the left, all other terms to the right

2c=-8

c=-8/2

c=-4

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