3b/(5b-7)=8/11

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Solution for 3b/(5b-7)=8/11 equation: 



3b/(5b-7)=8/11

We move all terms to the left:

3b/(5b-7)-(8/11)=0



Domain of the equation: (5b-7)!=0

We move all terms containing b to the left, all other terms to the right

5b!=7

b!=7/5

b!=1+2/5

b∈R



We add all the numbers together, and all the variables

3b/(5b-7)-(+8/11)=0

We get rid of parentheses

3b/(5b-7)-8/11=0

We calculate fractions


33b/(55b-77)+(-40b+56)/(55b-77)=0

We multiply all the terms by the denominator


33b+(-40b+56)=0

We get rid of parentheses

33b-40b+56=0

We add all the numbers together, and all the variables

-7b+56=0

We move all terms containing b to the left, all other terms to the right

-7b=-56

b=-56/-7

b=+8

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